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No no, it was my personal annotation because NormalizedNamedEntity( ) is the string that the node Exists create.

The ADF0 tree has 2 children, but Exists has only one, which like you can see is Contains. Contains is a Terminal and has no children, so where is the second branch of the ADF0 tree? And how can I evaluate something like this?

Greetings from Germany

Bojan

Von: Sean Luke
Gesendet: 17.05.2013 18:10
An: [log in to unmask]
Betreff: Re: Evaluating an ADF-Tree