Thanks, Sean, I’ll give it a try.

Rodrigo

> Em Dec 22, 2014, à(s) 8:41 PM, Sean Luke <[log in to unmask]> escreveu:
>
> On Dec 22, 2014, at 4:13 PM, Rodrigo Coelho Barros <[log in to unmask]> wrote:
>
>> I’m trying to build an EDA instead of a GA. I figured I could use the InitializationPipeline to always generate random individuals after each generation.
>> Nevertheless, if my pipeline consists of the InitializationPipeline alone (that is, pop.subpop.0.species.pipe = ec.breed.InitializationPipeline, and nothing else), I get an error that "num-sources value must be > 0”.
>
> Weird: InitializationPipeline worked in the past, and yet that would have been impossible. Your error report is completely right.
>
> The issue is that BreedingPipeline.DEFAULT_SOURCES = 0. So the logic followed for source loading is as follows:
>
> if (numSources() == DEFAULT_SOURCES) // this may return DEFAULT_SOURCES
> determine nummber of sources from the parameter file using "num-sources"
> if "num-sources" == 0, generate error
> else
> use numSources() as the number of sources
> load the sources
>
> The problem is that InitializationPipeline (properly) returns 0 for its numSources(). But since DEFAULT_SOURCES==0 this triggers BreedingPipeline to try loading the number of sources using num-sources. Since you (properly) don't have a num-sources parameter, BreedingPipeline freaks out.
>
> The fix is to set DEFAULT_SOURCES to -1. I've added in a little bit of better checking code in BreedingPipeline to deal with this.
>
> I also added in some more checking code in the two classes for which DEFAULT_SOURCES is relevant: MultipleVectorCrossoverPipeline and MultiBreedingPipeline, since it's now possible for num-sources=0 and they shouldn't permit that.
>
> The result is out on SVN, go grab it. Or if you like, here are the relevant changed files.
>
> <BreedingPipeline.java><MultipleVectorCrossoverPipeline.java><MultiBreedingPipeline.java>
>
> BTW, if you're trying to build an EDA, it might be easier to just make a custom breeder and avoid pipelines entirely.
>
> Sean
>